What are the solutions to the equation 22=3(x+3)^3-2 ?

The solutions to the equation 22=3(x+3)^3-2 are x=-1,x=-4+sqrt(3)i,x=-4-sqrt(3)i

Find the zeros of 22=3(x+3)^3-2

The zeros of 22=3(x+3)^3-2 are x=-1,x=-4+sqrt(3)i,x=-4-sqrt(3)i

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22 = 3 (x + 3)^{3} - 2

x = - 1, x = - 4 + 3 i, x = - 4 - 3 i

Solution steps

22 = 3 (x + 3)^{3} - 2

Switch sides

3 (x + 3)^{3} - 2 = 22

Move

2

to the right side

3 (x + 3)^{3} = 24

Divide both sides by

3

(x + 3)^{3} = 8

For

g^{3} (x) = f (a)

the solutions are

Solve

The solutions are

x = - 1, x = - 4 + 3 i, x = - 4 - 3 i

2 x^{3} - 13 x^{2} + 22 x - 8 = 0

x, y = x^{3} + 3

0 = x^{3} - 6 x^{2} + 32

x, y = x^{3} - 1

3 \cdot (x^{3} - 1) = - 27

What are the solutions to the equation 22=3(x+3)^3-2 ?
The solutions to the equation 22=3(x+3)^3-2 are x=-1,x=-4+sqrt(3)i,x=-4-sqrt(3)i
Find the zeros of 22=3(x+3)^3-2
The zeros of 22=3(x+3)^3-2 are x=-1,x=-4+sqrt(3)i,x=-4-sqrt(3)i