What are the solutions to the equation x^3-3x^2-28x+60=0 ?

The solutions to the equation x^3-3x^2-28x+60=0 are x=2,x=-5,x=6

Find the zeros of x^3-3x^2-28x+60=0

The zeros of x^3-3x^2-28x+60=0 are x=2,x=-5,x=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 3 x^{2} - 28 x + 60 = 0

x = 2, x = - 5, x = 6

Solution steps

x^{3} - 3 x^{2} - 28 x + 60 = 0

Factor

x^{3} - 3 x^{2} - 28 x + 60 : (x - 2) (x + 5) (x - 6)

(x - 2) (x + 5) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 5 = 0 or x - 6 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 5 = 0 : x = - 5

Solve

x - 6 = 0 : x = 6

The solutions are

x = 2, x = - 5, x = 6

35 = \frac{x ^{2} ( 4 x + 6 )}{2}

22 = 3 (x + 3)^{3} - 2

2 x^{3} - 13 x^{2} + 22 x - 8 = 0

x, y = x^{3} + 3

0 = x^{3} - 6 x^{2} + 32

What are the solutions to the equation x^3-3x^2-28x+60=0 ?
The solutions to the equation x^3-3x^2-28x+60=0 are x=2,x=-5,x=6
Find the zeros of x^3-3x^2-28x+60=0
The zeros of x^3-3x^2-28x+60=0 are x=2,x=-5,x=6