What are the solutions to the equation (x^2-8x+15)(x+1)=0 ?

The solutions to the equation (x^2-8x+15)(x+1)=0 are x=3,x=5,x=-1

Find the zeros of (x^2-8x+15)(x+1)=0

The zeros of (x^2-8x+15)(x+1)=0 are x=3,x=5,x=-1

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(x^{2} - 8 x + 15) (x + 1) = 0

x = 3, x = 5, x = - 1

Solution steps

(x^{2} - 8 x + 15) (x + 1) = 0

Factor

(x^{2} - 8 x + 15) (x + 1) : (x - 3) (x - 5) (x + 1)

(x - 3) (x - 5) (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x - 5 = 0 or x + 1 = 0

Solve

x - 3 = 0 : x = 3

Solve

x - 5 = 0 : x = 5

Solve

x + 1 = 0 : x = - 1

The solutions are

x = 3, x = 5, x = - 1

x^{4} - 4 x^{3} + 7 x^{2} - 8 x + 10 = 0

2 - 3 - 2 x^{4} - 3 x - 16 + 2 x - 3 = x + 12, a

- x^{5} - 1 = 0

y, 5 (y + 1)^{3} + x^{2} = 1

0 = 24 x^{3} + 2 x^{2} + x - 5

What are the solutions to the equation (x^2-8x+15)(x+1)=0 ?
The solutions to the equation (x^2-8x+15)(x+1)=0 are x=3,x=5,x=-1
Find the zeros of (x^2-8x+15)(x+1)=0
The zeros of (x^2-8x+15)(x+1)=0 are x=3,x=5,x=-1