What are the solutions to the equation -4x^4+5x^3-x^2=0 ?

The solutions to the equation -4x^4+5x^3-x^2=0 are x=0,x= 1/4 ,x=1

Find the zeros of -4x^4+5x^3-x^2=0

The zeros of -4x^4+5x^3-x^2=0 are x=0,x= 1/4 ,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{4} + 5 x^{3} - x^{2} = 0

x = 0, x = \frac{1}{4}, x = 1

Decimal Notation

x = 0, x = 0.25, x = 1

Solution steps

- 4 x^{4} + 5 x^{3} - x^{2} = 0

Factor

- 4 x^{4} + 5 x^{3} - x^{2} : - x^{2} (4 x - 1) (x - 1)

- x^{2} (4 x - 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x - 1 = 0 or x - 1 = 0

Solve

4 x - 1 = 0 : x = \frac{1}{4}

Solve

x - 1 = 0 : x = 1

The solutions are

x = 0, x = \frac{1}{4}, x = 1

6 x^{5} - 54 x = 0

x^{3} - 2 x^{2} - 14 x + 28 = 0

x, (2 x + 1)^{4} - 80 = 1

x^{4} - 2 x^{3} + x^{2} - 2 = 0

x^{6} - 7 x^{3} + 10 = 0

What are the solutions to the equation -4x^4+5x^3-x^2=0 ?
The solutions to the equation -4x^4+5x^3-x^2=0 are x=0,x= 1/4 ,x=1
Find the zeros of -4x^4+5x^3-x^2=0
The zeros of -4x^4+5x^3-x^2=0 are x=0,x= 1/4 ,x=1