What are the solutions to the equation 0.11=(1+r/(12))^{12}-1 ?

The solutions to the equation 0.11=(1+r/(12))^{12}-1 are r=0.10481…,r=-24.10481…

Find the zeros of 0.11=(1+r/(12))^{12}-1

The zeros of 0.11=(1+r/(12))^{12}-1 are r=0.10481…,r=-24.10481…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0.11 = (1 + \frac{r}{12})^{12} - 1

r = 0.10481 \dots, r = - 24.10481 \dots

Solution steps

0.11 = (1 + \frac{r}{12})^{12} - 1

Switch sides

(1 + \frac{r}{12})^{12} - 1 = 0.11

Move

1

to the right side

(1 + \frac{r}{12})^{12} = 1.11

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

r = 0.10481 \dots, r = - 24.10481 \dots

(- 1 - x)^{2} (- 1 - 2 x - x^{2})^{2} = 0

x (x^{2} - 9) = 0

x^{3} (22 - (\frac{x}{2})) = 18

4 x (x - 1)^{2} = 1

(x + 1) (x + 2)^{2} (x^{2} - 6 x + 10) = 0

What are the solutions to the equation 0.11=(1+r/(12))^{12}-1 ?
The solutions to the equation 0.11=(1+r/(12))^{12}-1 are r=0.10481…,r=-24.10481…
Find the zeros of 0.11=(1+r/(12))^{12}-1
The zeros of 0.11=(1+r/(12))^{12}-1 are r=0.10481…,r=-24.10481…