What are the solutions to the equation -x^2(x-2)(2-x)=0 ?

The solutions to the equation -x^2(x-2)(2-x)=0 are x=0,x=2

Find the zeros of -x^2(x-2)(2-x)=0

The zeros of -x^2(x-2)(2-x)=0 are x=0,x=2

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- x^{2} (x - 2) (2 - x) = 0

x = 0, x = 2

Solution steps

- x^{2} (x - 2) (2 - x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or 2 - x = 0

Solve

x - 2 = 0 : x = 2

Solve

2 - x = 0 : x = 2

The solutions are

x = 0, x = 2

x^{3} - 5 = - 7

x^{4} - 8 x^{2} + 9 = 0

6 x^{3} - 12 x^{2} + 6 x = 0

500 \cdot b^{3} = 10

2 x^{4} + 4 x^{2} = 0

What are the solutions to the equation -x^2(x-2)(2-x)=0 ?
The solutions to the equation -x^2(x-2)(2-x)=0 are x=0,x=2
Find the zeros of -x^2(x-2)(2-x)=0
The zeros of -x^2(x-2)(2-x)=0 are x=0,x=2