What are the solutions to the equation x^3+6x-20=0 ?

The solutions to the equation x^3+6x-20=0 are x=2,x=-1+3i,x=-1-3i

Find the zeros of x^3+6x-20=0

The zeros of x^3+6x-20=0 are x=2,x=-1+3i,x=-1-3i

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x^{3} + 6 x - 20 = 0

x = 2, x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

x^{3} + 6 x - 20 = 0

Factor

x^{3} + 6 x - 20 : (x - 2) (x^{2} + 2 x + 10)

(x - 2) (x^{2} + 2 x + 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} + 2 x + 10 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 2 x + 10 = 0 : x = - 1 + 3 i, x = - 1 - 3 i

The solutions are

x = 2, x = - 1 + 3 i, x = - 1 - 3 i

x^{3} - 9 x^{2} - 81 x - 729 = 0

x^{3} - 3 x^{2} + 3 x - 1 = 1

2 x^{4} - 21 x^{2} + 45 = 0

2 x^{3} = x^{2}

4 x^{3} + x^{2} - 36 x - 9 = 0

What are the solutions to the equation x^3+6x-20=0 ?
The solutions to the equation x^3+6x-20=0 are x=2,x=-1+3i,x=-1-3i
Find the zeros of x^3+6x-20=0
The zeros of x^3+6x-20=0 are x=2,x=-1+3i,x=-1-3i