What are the solutions to the equation (x+2)^4=81 ?

The solutions to the equation (x+2)^4=81 are x=1,x=-5

Find the zeros of (x+2)^4=81

The zeros of (x+2)^4=81 are x=1,x=-5

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(x + 2)^{4} = 81

x = 1, x = - 5

Solution steps

(x + 2)^{4} = 81

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 1, x = - 5

5 = 4 x^{3} + 12 x^{2} + 12 x + 4

(m - 1)^{2} (m^{2} + 1)^{2} = 0

x^{3} + 6 x + 9 x = 0

2 x^{4} = 128 x

x, 2 x y - x^{3} = 0

What are the solutions to the equation (x+2)^4=81 ?
The solutions to the equation (x+2)^4=81 are x=1,x=-5
Find the zeros of (x+2)^4=81
The zeros of (x+2)^4=81 are x=1,x=-5