What are the solutions to the equation 3x^2*2x=162 ?

The solutions to the equation 3x^2*2x=162 are x=3,x=-3/2+(3sqrt(3))/2 i,x=-3/2-(3sqrt(3))/2 i

Find the zeros of 3x^2*2x=162

The zeros of 3x^2*2x=162 are x=3,x=-3/2+(3sqrt(3))/2 i,x=-3/2-(3sqrt(3))/2 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} \cdot 2 x = 162

x = 3, x = - \frac{3}{2} + \frac{3 3}{2} i, x = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

3 x^{2} \cdot 2 x = 162

Simplify

6 x^{3} = 162

Divide both sides by

6

\frac{6 x ^{3}}{6} = \frac{162}{6}

x^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

x = 3, x = - \frac{3}{2} + \frac{3 3}{2} i, x = - \frac{3}{2} - \frac{3 3}{2} i

x (x + 2) (x - 4) = 2

x^{4} + 3 x^{3} - 3 x^{2} - 7 x + 6 = 0

(2 x - 5)^{5} = 243

x^{4} + 16 i = 0

2 x^{3} - 3 x^{2} - 36 x = 0

What are the solutions to the equation 3x^2*2x=162 ?
The solutions to the equation 3x^2*2x=162 are x=3,x=-3/2+(3sqrt(3))/2 i,x=-3/2-(3sqrt(3))/2 i
Find the zeros of 3x^2*2x=162
The zeros of 3x^2*2x=162 are x=3,x=-3/2+(3sqrt(3))/2 i,x=-3/2-(3sqrt(3))/2 i