What are the solutions to the equation 0=x^4+4x+3 ?

The solutions to the equation 0=x^4+4x+3 are x=-1,x=1+sqrt(2)i,x=1-sqrt(2)i

Find the zeros of 0=x^4+4x+3

The zeros of 0=x^4+4x+3 are x=-1,x=1+sqrt(2)i,x=1-sqrt(2)i

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0 = x^{4} + 4 x + 3

x = - 1, x = 1 + 2 i, x = 1 - 2 i

Solution steps

0 = x^{4} + 4 x + 3

Switch sides

x^{4} + 4 x + 3 = 0

Factor

x^{4} + 4 x + 3 : (x + 1)^{2} (x^{2} - 2 x + 3)

(x + 1)^{2} (x^{2} - 2 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} - 2 x + 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} - 2 x + 3 = 0 : x = 1 + 2 i, x = 1 - 2 i

The solutions are

x = - 1, x = 1 + 2 i, x = 1 - 2 i

x (x^{2} + 5 x + 8) = 0

x^{3} - 9 x^{2} + 14 x = 0

- 12 x^{2} (x^{3} + 2) = 0

x^{3} + 2 x - 42 = 0

50 (1 + r)^{12} = 10

What are the solutions to the equation 0=x^4+4x+3 ?
The solutions to the equation 0=x^4+4x+3 are x=-1,x=1+sqrt(2)i,x=1-sqrt(2)i
Find the zeros of 0=x^4+4x+3
The zeros of 0=x^4+4x+3 are x=-1,x=1+sqrt(2)i,x=1-sqrt(2)i