What are the solutions to the equation -x^3+4*x^2+x-4=0 ?

The solutions to the equation -x^3+4*x^2+x-4=0 are x=4,x=-1,x=1

Find the zeros of -x^3+4*x^2+x-4=0

The zeros of -x^3+4*x^2+x-4=0 are x=4,x=-1,x=1

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- x^{3} + 4 \cdot x^{2} + x - 4 = 0

x = 4, x = - 1, x = 1

Solution steps

- x^{3} + 4 x^{2} + x - 4 = 0

Factor

- x^{3} + 4 x^{2} + x - 4 : - (x - 4) (x + 1) (x - 1)

- (x - 4) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 4, x = - 1, x = 1

x^{3} + 3^{3} = 0

m^{3} - 6 m^{2} + 12 m + 208 = 0

(\frac{x \cdot 4 - 7}{3})^{3} = 27

4 x^{14} - 57 = 37

52 x^{6} = x - 23 x

What are the solutions to the equation -x^3+4*x^2+x-4=0 ?
The solutions to the equation -x^3+4*x^2+x-4=0 are x=4,x=-1,x=1
Find the zeros of -x^3+4*x^2+x-4=0
The zeros of -x^3+4*x^2+x-4=0 are x=4,x=-1,x=1