What are the solutions to the equation ((x*4-7)/3)^3=27 ?

The solutions to the equation ((x*4-7)/3)^3=27 are x=4,x= 5/8+i(9sqrt(3))/8 ,x= 5/8-i(9sqrt(3))/8

Find the zeros of ((x*4-7)/3)^3=27

The zeros of ((x*4-7)/3)^3=27 are x=4,x= 5/8+i(9sqrt(3))/8 ,x= 5/8-i(9sqrt(3))/8

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(\frac{x \cdot 4 - 7}{3})^{3} = 27

x = 4, x = \frac{5}{8} + i \frac{9 3}{8}, x = \frac{5}{8} - i \frac{9 3}{8}

Solution steps

(\frac{x \cdot 4 - 7}{3})^{3} = 27

For

g^{3} (x) = f (a)

the solutions are

Solve

The solutions are

x = 4, x = \frac{5}{8} + i \frac{9 3}{8}, x = \frac{5}{8} - i \frac{9 3}{8}

4 x^{14} - 57 = 37

52 x^{6} = x - 23 x

51 = 4 x^{4} - 13

x^{3} - 4 x = 5

x^{4} - 2 x^{2} - 3 x - 2 = 0

What are the solutions to the equation ((x*4-7)/3)^3=27 ?
The solutions to the equation ((x*4-7)/3)^3=27 are x=4,x= 5/8+i(9sqrt(3))/8 ,x= 5/8-i(9sqrt(3))/8
Find the zeros of ((x*4-7)/3)^3=27
The zeros of ((x*4-7)/3)^3=27 are x=4,x= 5/8+i(9sqrt(3))/8 ,x= 5/8-i(9sqrt(3))/8