What are the solutions to the equation 2a^4-15a^2+28=0 ?

The solutions to the equation 2a^4-15a^2+28=0 are a=2,a=-2,a=sqrt(7/2),a=-sqrt(7/2)

Find the zeros of 2a^4-15a^2+28=0

The zeros of 2a^4-15a^2+28=0 are a=2,a=-2,a=sqrt(7/2),a=-sqrt(7/2)

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2 a^{4} - 15 a^{2} + 28 = 0

a = 2, a = - 2, a = \frac{7}{2}, a = - \frac{7}{2}

Decimal Notation

a = 2, a = - 2, a = 1.87082 \dots, a = - 1.87082 \dots

Solution steps

2 a^{4} - 15 a^{2} + 28 = 0

Rewrite the equation with

u = a^{2}

and

u^{2} = a^{4}

2 u^{2} - 15 u + 28 = 0

Solve

2 u^{2} - 15 u + 28 = 0 : u = 4, u = \frac{7}{2}

u = 4, u = \frac{7}{2}

Substitute back

u = a^{2},

solve for

a

Solve

a^{2} = 4 : a = 2, a = - 2

Solve

a^{2} = \frac{7}{2} : a = \frac{7}{2}, a = - \frac{7}{2}

The solutions are

a = 2, a = - 2, a = \frac{7}{2}, a = - \frac{7}{2}

4 x^{2} (x - 1) + 2 x (x - 1) = 0

5 x^{4} - 1 2^{3} = 0

(x + 1) (x - 2)^{2} = 0

π \cdot r^{4} = 4.86 \cdot 1 0^{- 7}

x^{4} - 265 x^{2} + 1 = 0

What are the solutions to the equation 2a^4-15a^2+28=0 ?
The solutions to the equation 2a^4-15a^2+28=0 are a=2,a=-2,a=sqrt(7/2),a=-sqrt(7/2)
Find the zeros of 2a^4-15a^2+28=0
The zeros of 2a^4-15a^2+28=0 are a=2,a=-2,a=sqrt(7/2),a=-sqrt(7/2)