What are the solutions to the equation s(s+3)(s^2+2s+2)=0 ?

The solutions to the equation s(s+3)(s^2+2s+2)=0 are s=0,s=-3,s=-1+i,s=-1-i

Find the zeros of s(s+3)(s^2+2s+2)=0

The zeros of s(s+3)(s^2+2s+2)=0 are s=0,s=-3,s=-1+i,s=-1-i

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s (s + 3) (s^{2} + 2 s + 2) = 0

s = 0, s = - 3, s = - 1 + i, s = - 1 - i

Solution steps

s (s + 3) (s^{2} + 2 s + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

s = 0 or s + 3 = 0 or s^{2} + 2 s + 2 = 0

Solve

s + 3 = 0 : s = - 3

Solve

s^{2} + 2 s + 2 = 0 : s = - 1 + i, s = - 1 - i

The solutions are

s = 0, s = - 3, s = - 1 + i, s = - 1 - i

\frac{256}{625} = 100 r^{6}

n^{3} = 343

4 X^{3} = 2 X^{2}

2 x^{3} + 3 x^{2} - 2 x - 3 = 0

3 w - w^{3} = 2

What are the solutions to the equation s(s+3)(s^2+2s+2)=0 ?
The solutions to the equation s(s+3)(s^2+2s+2)=0 are s=0,s=-3,s=-1+i,s=-1-i
Find the zeros of s(s+3)(s^2+2s+2)=0
The zeros of s(s+3)(s^2+2s+2)=0 are s=0,s=-3,s=-1+i,s=-1-i