What are the solutions to the equation X^3-X^2-4X+4=0 ?

The solutions to the equation X^3-X^2-4X+4=0 are X=1,X=-2,X=2

Find the zeros of X^3-X^2-4X+4=0

The zeros of X^3-X^2-4X+4=0 are X=1,X=-2,X=2

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X^{3} - X^{2} - 4 X + 4 = 0

X = 1, X = - 2, X = 2

Solution steps

X^{3} - X^{2} - 4 X + 4 = 0

Factor

X^{3} - X^{2} - 4 X + 4 : (X - 1) (X + 2) (X - 2)

(X - 1) (X + 2) (X - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

X - 1 = 0 or X + 2 = 0 or X - 2 = 0

Solve

X - 1 = 0 : X = 1

Solve

X + 2 = 0 : X = - 2

Solve

X - 2 = 0 : X = 2

The solutions are

X = 1, X = - 2, X = 2

- 3 x^{3} + 2 x^{2} + x = 0

(1 + x^{2})^{2} = 4 (1 - x^{2})

x^{3} + 6 = 12

x^{4} + 5 x^{2} - 50 = 0

128 x^{3} - 16 x = 0

What are the solutions to the equation X^3-X^2-4X+4=0 ?
The solutions to the equation X^3-X^2-4X+4=0 are X=1,X=-2,X=2
Find the zeros of X^3-X^2-4X+4=0
The zeros of X^3-X^2-4X+4=0 are X=1,X=-2,X=2