What are the solutions to the equation 20=[(5+(0.12x))/(10)]^{20} ?

The solutions to the equation 20=[(5+(0.12x))/(10)]^{20} are x=55.13219…,x=-138.46552…

Find the zeros of 20=[(5+(0.12x))/(10)]^{20}

The zeros of 20=[(5+(0.12x))/(10)]^{20} are x=55.13219…,x=-138.46552…

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20 = [\frac{5 + ( 0.12 x )}{10}]^{20}

x = 55.13219 \dots, x = - 138.46552 \dots

Solution steps

20 = [\frac{5 + ( 0.12 x )}{10}]^{20}

Switch sides

[\frac{5 + ( 0.12 x )}{10}]^{20} = 20

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 55.13219 \dots, x = - 138.46552 \dots

y^{3} + y^{2} - 3 y - 3 = 0

(x - 4) (x^{2} + 4 x + 16) = - 37

L^{3} = 1927

(x - 3)^{4} = 21

w^{3} = 343

What are the solutions to the equation 20=[(5+(0.12x))/(10)]^{20} ?
The solutions to the equation 20=[(5+(0.12x))/(10)]^{20} are x=55.13219…,x=-138.46552…
Find the zeros of 20=[(5+(0.12x))/(10)]^{20}
The zeros of 20=[(5+(0.12x))/(10)]^{20} are x=55.13219…,x=-138.46552…