What are the solutions to the equation 0=2x^3+x^2-5x+2 ?

The solutions to the equation 0=2x^3+x^2-5x+2 are x=1,x= 1/2 ,x=-2

Find the zeros of 0=2x^3+x^2-5x+2

The zeros of 0=2x^3+x^2-5x+2 are x=1,x= 1/2 ,x=-2

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0 = 2 x^{3} + x^{2} - 5 x + 2

x = 1, x = \frac{1}{2}, x = - 2

Decimal Notation

x = 1, x = 0.5, x = - 2

Solution steps

0 = 2 x^{3} + x^{2} - 5 x + 2

Switch sides

2 x^{3} + x^{2} - 5 x + 2 = 0

Factor

2 x^{3} + x^{2} - 5 x + 2 : (x - 1) (2 x - 1) (x + 2)

(x - 1) (2 x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x - 1 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 1, x = \frac{1}{2}, x = - 2

(x^{2} - 6 x + 10)^{2} = 0

x^{10} = 9 x^{8}

x^{3} = - x^{2} + 2 x

9 x (2 x + 1)^{3} = 4 x (2 x + 1)

(4 x - 1) (5 x^{3} - 8.64) = 0

What are the solutions to the equation 0=2x^3+x^2-5x+2 ?
The solutions to the equation 0=2x^3+x^2-5x+2 are x=1,x= 1/2 ,x=-2
Find the zeros of 0=2x^3+x^2-5x+2
The zeros of 0=2x^3+x^2-5x+2 are x=1,x= 1/2 ,x=-2