What are the solutions to the equation 4x^3+16x^2-9x-36=0 ?

The solutions to the equation 4x^3+16x^2-9x-36=0 are x=-4,x=-3/2 ,x= 3/2

Find the zeros of 4x^3+16x^2-9x-36=0

The zeros of 4x^3+16x^2-9x-36=0 are x=-4,x=-3/2 ,x= 3/2

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4 x^{3} + 16 x^{2} - 9 x - 36 = 0

x = - 4, x = - \frac{3}{2}, x = \frac{3}{2}

Decimal Notation

x = - 4, x = - 1.5, x = 1.5

Solution steps

4 x^{3} + 16 x^{2} - 9 x - 36 = 0

Factor

4 x^{3} + 16 x^{2} - 9 x - 36 : (x + 4) (2 x + 3) (2 x - 3)

(x + 4) (2 x + 3) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or 2 x + 3 = 0 or 2 x - 3 = 0

Solve

x + 4 = 0 : x = - 4

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = - 4, x = - \frac{3}{2}, x = \frac{3}{2}

9 a^{3} - 441 a = - 4 a^{2} + 196

\frac{2 - i}{1 + 2 i} \cdot z^{4} = 1

x^{3} + x^{2} + 2 x + 1 = 0

x^{3} - 40 x^{2} + 404 x - 80 = 0

(x + 2) (x + 3) (x + 8) (x + 12) = 54 x^{2}

What are the solutions to the equation 4x^3+16x^2-9x-36=0 ?
The solutions to the equation 4x^3+16x^2-9x-36=0 are x=-4,x=-3/2 ,x= 3/2
Find the zeros of 4x^3+16x^2-9x-36=0
The zeros of 4x^3+16x^2-9x-36=0 are x=-4,x=-3/2 ,x= 3/2