What are the solutions to the equation 2c^3+4c^2-126c=0 ?

The solutions to the equation 2c^3+4c^2-126c=0 are c=0,c=7,c=-9

Find the zeros of 2c^3+4c^2-126c=0

The zeros of 2c^3+4c^2-126c=0 are c=0,c=7,c=-9

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2 c^{3} + 4 c^{2} - 126 c = 0

c = 0, c = 7, c = - 9

Solution steps

2 c^{3} + 4 c^{2} - 126 c = 0

Factor

2 c^{3} + 4 c^{2} - 126 c : 2 c (c - 7) (c + 9)

2 c (c - 7) (c + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

c = 0 or c - 7 = 0 or c + 9 = 0

Solve

c - 7 = 0 : c = 7

Solve

c + 9 = 0 : c = - 9

The solutions are

c = 0, c = 7, c = - 9

- x^{3} + 11 x^{2} - 43 x + 25 = 0

q^{3} - q = 34 + 32 q

2 x^{3} + x + 1 = 0

x^{4} - 2 x^{3} + 5 x^{2} - 6 = 0

a, 2 f = 5 a^{5}

What are the solutions to the equation 2c^3+4c^2-126c=0 ?
The solutions to the equation 2c^3+4c^2-126c=0 are c=0,c=7,c=-9
Find the zeros of 2c^3+4c^2-126c=0
The zeros of 2c^3+4c^2-126c=0 are c=0,c=7,c=-9