What are the solutions to the equation 2x^5-32x=0 ?

The solutions to the equation 2x^5-32x=0 are x=0,x=2i,x=-2i,x=-2,x=2

Find the zeros of 2x^5-32x=0

The zeros of 2x^5-32x=0 are x=0,x=2i,x=-2i,x=-2,x=2

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2 x^{5} - 32 x = 0

x = 0, x = 2 i, x = - 2 i, x = - 2, x = 2

Solution steps

2 x^{5} - 32 x = 0

Factor

2 x^{5} - 32 x : 2 x (x^{2} + 4) (x + 2) (x - 2)

2 x (x^{2} + 4) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 4 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = 2 i, x = - 2 i, x = - 2, x = 2

4 x^{3} - 12 x^{2} + 16 = 0

x^{2} (4 x - 3) (5 x - 1) = 0

x^{8} = 1 0^{72}

x^{3} - 7 x^{2} + 13 x - 3 = 0

- x^{3} + 14 x^{2} - 42 x = 0

What are the solutions to the equation 2x^5-32x=0 ?
The solutions to the equation 2x^5-32x=0 are x=0,x=2i,x=-2i,x=-2,x=2
Find the zeros of 2x^5-32x=0
The zeros of 2x^5-32x=0 are x=0,x=2i,x=-2i,x=-2,x=2