What are the solutions to the equation 2300000=2000000*(1+x)^6 ?

The solutions to the equation 2300000=2000000*(1+x)^6 are x=\sqrt[6]{23/20}-1,x=-\sqrt[6]{23/20}-1

Find the zeros of 2300000=2000000*(1+x)^6

The zeros of 2300000=2000000*(1+x)^6 are x=\sqrt[6]{23/20}-1,x=-\sqrt[6]{23/20}-1

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2300000 = 2000000 \cdot (1 + x)^{6}

Decimal Notation

x = 0.02356 \dots, x = - 2.02356 \dots

Solution steps

2300000 = 2000000 (1 + x)^{6}

Switch sides

2000000 (1 + x)^{6} = 2300000

Divide both sides by

2000000

(1 + x)^{6} = \frac{23}{20}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

13 + x^{3} = 7 x^{2} + 13

x^{30} = 3

x^{4} + x^{3} = x^{4} + x^{2} + 6 x

(x) = (5 x^{2} - 3) (x^{2} + x + 4)

s^{3} + 3 s^{2} + 2 s + 1 = 0

What are the solutions to the equation 2300000=2000000*(1+x)^6 ?
The solutions to the equation 2300000=2000000*(1+x)^6 are x=\sqrt[6]{23/20}-1,x=-\sqrt[6]{23/20}-1
Find the zeros of 2300000=2000000*(1+x)^6
The zeros of 2300000=2000000*(1+x)^6 are x=\sqrt[6]{23/20}-1,x=-\sqrt[6]{23/20}-1