What are the solutions to the equation 13+x^3=7x^2+13 ?

The solutions to the equation 13+x^3=7x^2+13 are x=0,x=7

Find the zeros of 13+x^3=7x^2+13

The zeros of 13+x^3=7x^2+13 are x=0,x=7

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13 + x^{3} = 7 x^{2} + 13

x = 0, x = 7

Solution steps

13 + x^{3} = 7 x^{2} + 13

Move

13

to the right side

x^{3} = 7 x^{2}

Move

7 x^{2}

to the left side

x^{3} - 7 x^{2} = 0

Factor

x^{3} - 7 x^{2} : x^{2} (x - 7)

x^{2} (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 7 = 0

Solve

x - 7 = 0 : x = 7

The solutions are

x = 0, x = 7

x^{30} = 3

x^{4} + x^{3} = x^{4} + x^{2} + 6 x

(x) = (5 x^{2} - 3) (x^{2} + x + 4)

s^{3} + 3 s^{2} + 2 s + 1 = 0

x^{4} - 3 x^{3} + 5 x^{2} - 27 x - 36 = 0

What are the solutions to the equation 13+x^3=7x^2+13 ?
The solutions to the equation 13+x^3=7x^2+13 are x=0,x=7
Find the zeros of 13+x^3=7x^2+13
The zeros of 13+x^3=7x^2+13 are x=0,x=7