What are the solutions to the equation x^4+x^3=x^4+x^2+6x ?

The solutions to the equation x^4+x^3=x^4+x^2+6x are x=0,x=-2,x=3

Find the zeros of x^4+x^3=x^4+x^2+6x

The zeros of x^4+x^3=x^4+x^2+6x are x=0,x=-2,x=3

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x^{4} + x^{3} = x^{4} + x^{2} + 6 x

x = 0, x = - 2, x = 3

Solution steps

x^{4} + x^{3} = x^{4} + x^{2} + 6 x

Switch sides

x^{4} + x^{2} + 6 x = x^{4} + x^{3}

Move

x^{3}

to the left side

x^{4} + x^{2} + 6 x - x^{3} = x^{4}

Move

x^{4}

to the left side

- x^{3} + x^{2} + 6 x = 0

Factor

- x^{3} + x^{2} + 6 x : - x (x + 2) (x - 3)

- x (x + 2) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

The solutions are

x = 0, x = - 2, x = 3

(x) = (5 x^{2} - 3) (x^{2} + x + 4)

s^{3} + 3 s^{2} + 2 s + 1 = 0

x^{4} - 3 x^{3} + 5 x^{2} - 27 x - 36 = 0

x^{5} - x^{4} - x^{3} + x^{2} = 0

(1 + \frac{x}{12})^{12} = 0.12

What are the solutions to the equation x^4+x^3=x^4+x^2+6x ?
The solutions to the equation x^4+x^3=x^4+x^2+6x are x=0,x=-2,x=3
Find the zeros of x^4+x^3=x^4+x^2+6x
The zeros of x^4+x^3=x^4+x^2+6x are x=0,x=-2,x=3