What are the solutions to the equation 0=x^3-3x^2-x+3 ?

The solutions to the equation 0=x^3-3x^2-x+3 are x=3,x=-1,x=1

Find the zeros of 0=x^3-3x^2-x+3

The zeros of 0=x^3-3x^2-x+3 are x=3,x=-1,x=1

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0 = x^{3} - 3 x^{2} - x + 3

x = 3, x = - 1, x = 1

Solution steps

0 = x^{3} - 3 x^{2} - x + 3

Switch sides

x^{3} - 3 x^{2} - x + 3 = 0

Factor

x^{3} - 3 x^{2} - x + 3 : (x - 3) (x + 1) (x - 1)

(x - 3) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 3, x = - 1, x = 1

9 x^{3} + x^{2} - 81 x - 9 = 0

x = x^{3} + 1

12 x^{3} = - 3 x^{2} - 12

\frac{256}{3125} x^{5} = 1

4 c^{3} + 24 c^{2} - 64 c = 0

What are the solutions to the equation 0=x^3-3x^2-x+3 ?
The solutions to the equation 0=x^3-3x^2-x+3 are x=3,x=-1,x=1
Find the zeros of 0=x^3-3x^2-x+3
The zeros of 0=x^3-3x^2-x+3 are x=3,x=-1,x=1