What are the solutions to the equation 6(5x^4-6x^2+1)=0 ?

The solutions to the equation 6(5x^4-6x^2+1)=0 are x=-1,x=1,x=-1/(sqrt(5)),x= 1/(sqrt(5))

Find the zeros of 6(5x^4-6x^2+1)=0

The zeros of 6(5x^4-6x^2+1)=0 are x=-1,x=1,x=-1/(sqrt(5)),x= 1/(sqrt(5))

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6 (5 x^{4} - 6 x^{2} + 1) = 0

x = - 1, x = 1, x = - \frac{1}{5}, x = \frac{1}{5}

Decimal Notation

x = - 1, x = 1, x = - 0.4472135955, x = 0.4472135955

Solution steps

6 (5 x^{4} - 6 x^{2} + 1) = 0

Factor

6 (5 x^{4} - 6 x^{2} + 1) : 6 (x + 1) (x - 1) (5 x + 1) (5 x - 1)

6 (x + 1) (x - 1) (5 x + 1) (5 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0 or 5 x + 1 = 0 or 5 x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

5 x + 1 = 0 : x = - \frac{1}{5}

Solve

5 x - 1 = 0 : x = \frac{1}{5}

The solutions are

x = - 1, x = 1, x = - \frac{1}{5}, x = \frac{1}{5}

y^{3} + 0.5 y = 0

6804 = 3780 (1 + r)^{4}

7 + 10 + 63 - 40 + 89 - 88 + 101 - 140 = x^{5}

x^{3} = 35 (3) + 20

2 x^{4} + 5 x^{2} - 3 = 0

What are the solutions to the equation 6(5x^4-6x^2+1)=0 ?
The solutions to the equation 6(5x^4-6x^2+1)=0 are x=-1,x=1,x=-1/(sqrt(5)),x= 1/(sqrt(5))
Find the zeros of 6(5x^4-6x^2+1)=0
The zeros of 6(5x^4-6x^2+1)=0 are x=-1,x=1,x=-1/(sqrt(5)),x= 1/(sqrt(5))