What are the solutions to the equation 0=x^3+2x^2-9x-18 ?

The solutions to the equation 0=x^3+2x^2-9x-18 are x=-2,x=-3,x=3

Find the zeros of 0=x^3+2x^2-9x-18

The zeros of 0=x^3+2x^2-9x-18 are x=-2,x=-3,x=3

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0 = x^{3} + 2 x^{2} - 9 x - 18

x = - 2, x = - 3, x = 3

Solution steps

0 = x^{3} + 2 x^{2} - 9 x - 18

Switch sides

x^{3} + 2 x^{2} - 9 x - 18 = 0

Factor

x^{3} + 2 x^{2} - 9 x - 18 : (x + 2) (x + 3) (x - 3)

(x + 2) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 2, x = - 3, x = 3

π \cdot r^{3} = \frac{1}{4}

c^{3} - 5 c^{2} + 7 c - 109 = 0

x, f = 5 x^{3} + 1 f (- 8)

- 12 = 5 (6 x^{4}) 7 (x^{6})

(x + 1)^{3} - 27 = 0

What are the solutions to the equation 0=x^3+2x^2-9x-18 ?
The solutions to the equation 0=x^3+2x^2-9x-18 are x=-2,x=-3,x=3
Find the zeros of 0=x^3+2x^2-9x-18
The zeros of 0=x^3+2x^2-9x-18 are x=-2,x=-3,x=3