What are the solutions to the equation 2x^3-5x^2-2x+5=0 ?

The solutions to the equation 2x^3-5x^2-2x+5=0 are x= 5/2 ,x=-1,x=1

Find the zeros of 2x^3-5x^2-2x+5=0

The zeros of 2x^3-5x^2-2x+5=0 are x= 5/2 ,x=-1,x=1

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2 x^{3} - 5 x^{2} - 2 x + 5 = 0

x = \frac{5}{2}, x = - 1, x = 1

Decimal Notation

x = 2.5, x = - 1, x = 1

Solution steps

2 x^{3} - 5 x^{2} - 2 x + 5 = 0

Factor

2 x^{3} - 5 x^{2} - 2 x + 5 : (2 x - 5) (x + 1) (x - 1)

(2 x - 5) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 5 = 0 or x + 1 = 0 or x - 1 = 0

Solve

2 x - 5 = 0 : x = \frac{5}{2}

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = \frac{5}{2}, x = - 1, x = 1

t, (t^{4} - 1)^{2} = x

(1 + x)^{12} = 1.12

(1 + x)^{12} = 1.15

- x^{3} - 36 x^{2} - 416 x - 1552 = 0

x^{3} - x^{2} - x + 5 = 0

What are the solutions to the equation 2x^3-5x^2-2x+5=0 ?
The solutions to the equation 2x^3-5x^2-2x+5=0 are x= 5/2 ,x=-1,x=1
Find the zeros of 2x^3-5x^2-2x+5=0
The zeros of 2x^3-5x^2-2x+5=0 are x= 5/2 ,x=-1,x=1