What are the solutions to the equation m^3= 1/125 ?

The solutions to the equation m^3= 1/125 are m= 1/5 ,m=-1/10+(sqrt(3))/(10)i,m=-1/10-(sqrt(3))/(10)i

Find the zeros of m^3= 1/125

The zeros of m^3= 1/125 are m= 1/5 ,m=-1/10+(sqrt(3))/(10)i,m=-1/10-(sqrt(3))/(10)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{3} = \frac{1}{125}

m = \frac{1}{5}, m = - \frac{1}{10} + \frac{3}{10} i, m = - \frac{1}{10} - \frac{3}{10} i

Solution steps

m^{3} = \frac{1}{125}

For

x^{3} = f (a)

the solutions are

Simplify

m = \frac{1}{5}, m = - \frac{1}{10} + \frac{3}{10} i, m = - \frac{1}{10} - \frac{3}{10} i

2 x^{4} + 6 x^{3} - 8 x^{2} - 24 x = 0

2 x (x^{3} - 216) = 0

x^{4} + 2 x^{3} - 14 x^{2} + 2 x + 1 = 0

0.5 (5 - 7 x) = 8 - (4 x^{6})

x, x^{4} + y^{4} = 2

What are the solutions to the equation m^3= 1/125 ?
The solutions to the equation m^3= 1/125 are m= 1/5 ,m=-1/10+(sqrt(3))/(10)i,m=-1/10-(sqrt(3))/(10)i
Find the zeros of m^3= 1/125
The zeros of m^3= 1/125 are m= 1/5 ,m=-1/10+(sqrt(3))/(10)i,m=-1/10-(sqrt(3))/(10)i