What are the solutions to the equation 2x+x^5+x^2=4 ?

The solutions to the equation 2x+x^5+x^2=4 are x=1

Find the zeros of 2x+x^5+x^2=4

The zeros of 2x+x^5+x^2=4 are x=1

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2 x + x^{5} + x^{2} = 4

x = 1

Solution steps

2 x + x^{5} + x^{2} = 4

Move

4

to the left side

2 x + x^{5} + x^{2} - 4 = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{5} + x^{2} + 2 x - 4 = 0

Factor

x^{5} + x^{2} + 2 x - 4 : (x - 1) (x^{4} + x^{3} + x^{2} + 2 x + 4)

(x - 1) (x^{4} + x^{3} + x^{2} + 2 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{4} + x^{3} + x^{2} + 2 x + 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{4} + x^{3} + x^{2} + 2 x + 4 = 0 :

No Solution for

x \in R

The solution is

x = 1

6500 = 6000 (1 + \frac{r}{4})^{24}

x^{3} + 6 x^{2} - 24 x - 64 = 0

t^{4} - 11 t^{2} + 18 = 0

x^{3} + 3 x^{2} - 13 x - 15 = 0

x^{3} + 2 x^{2} - 8 x = 16

What are the solutions to the equation 2x+x^5+x^2=4 ?
The solutions to the equation 2x+x^5+x^2=4 are x=1
Find the zeros of 2x+x^5+x^2=4
The zeros of 2x+x^5+x^2=4 are x=1