What are the solutions to the equation x^3+2x^2-8x=16 ?

The solutions to the equation x^3+2x^2-8x=16 are x=-2,x=-2sqrt(2),x=2sqrt(2)

Find the zeros of x^3+2x^2-8x=16

The zeros of x^3+2x^2-8x=16 are x=-2,x=-2sqrt(2),x=2sqrt(2)

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x^{3} + 2 x^{2} - 8 x = 16

x = - 2, x = - 22, x = 22

Decimal Notation

x = - 2, x = - 2.82842 \dots, x = 2.82842 \dots

Solution steps

x^{3} + 2 x^{2} - 8 x = 16

Move

16

to the left side

x^{3} + 2 x^{2} - 8 x - 16 = 0

Factor

x^{3} + 2 x^{2} - 8 x - 16 : (x + 2) (x + 22) (x - 22)

(x + 2) (x + 22) (x - 22) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 22 = 0 or x - 22 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 22 = 0 : x = - 22

Solve

x - 22 = 0 : x = 22

The solutions are

x = - 2, x = - 22, x = 22

2 x (x^{2} - 3) = 0

16 x^{4} - 32 x^{3} + 24 x^{2} - 8 x + 1 = 0

x^{3} = 6 x^{2} + 3 x + 10

5 = k^{6}

z^{4} = 3 + 2 i

What are the solutions to the equation x^3+2x^2-8x=16 ?
The solutions to the equation x^3+2x^2-8x=16 are x=-2,x=-2sqrt(2),x=2sqrt(2)
Find the zeros of x^3+2x^2-8x=16
The zeros of x^3+2x^2-8x=16 are x=-2,x=-2sqrt(2),x=2sqrt(2)