What are the solutions to the equation 6500=6000(1+r/4)^{24} ?

The solutions to the equation 6500=6000(1+r/4)^{24} are r=4\sqrt[24]{13/12}-4,r=-4\sqrt[24]{13/12}-4

Find the zeros of 6500=6000(1+r/4)^{24}

The zeros of 6500=6000(1+r/4)^{24} are r=4\sqrt[24]{13/12}-4,r=-4\sqrt[24]{13/12}-4

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6500 = 6000 (1 + \frac{r}{4})^{24}

Decimal Notation

r = 0.01336 \dots, r = - 8.01336 \dots

Solution steps

6500 = 6000 (1 + \frac{r}{4})^{24}

Switch sides

6000 (1 + \frac{r}{4})^{24} = 6500

Divide both sides by

6000

(1 + \frac{r}{4})^{24} = \frac{13}{12}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x^{3} + 6 x^{2} - 24 x - 64 = 0

t^{4} - 11 t^{2} + 18 = 0

x^{3} + 3 x^{2} - 13 x - 15 = 0

x^{3} + 2 x^{2} - 8 x = 16

2 x (x^{2} - 3) = 0

What are the solutions to the equation 6500=6000(1+r/4)^{24} ?
The solutions to the equation 6500=6000(1+r/4)^{24} are r=4\sqrt[24]{13/12}-4,r=-4\sqrt[24]{13/12}-4
Find the zeros of 6500=6000(1+r/4)^{24}
The zeros of 6500=6000(1+r/4)^{24} are r=4\sqrt[24]{13/12}-4,r=-4\sqrt[24]{13/12}-4