What are the solutions to the equation 2x(x^2-3)=0 ?

The solutions to the equation 2x(x^2-3)=0 are x=0,x=-sqrt(3),x=sqrt(3)

Find the zeros of 2x(x^2-3)=0

The zeros of 2x(x^2-3)=0 are x=0,x=-sqrt(3),x=sqrt(3)

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2 x (x^{2} - 3) = 0

x = 0, x = - 3, x = 3

Decimal Notation

x = 0, x = - 1.73205 \dots, x = 1.73205 \dots

Solution steps

2 x (x^{2} - 3) = 0

Factor

2 x (x^{2} - 3) : 2 x (x + 3) (x - 3)

2 x (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 0, x = - 3, x = 3

16 x^{4} - 32 x^{3} + 24 x^{2} - 8 x + 1 = 0

x^{3} = 6 x^{2} + 3 x + 10

5 = k^{6}

z^{4} = 3 + 2 i

x^{4} + 6 x^{3} + 18 x^{2} + 22 x + 17 = 0

What are the solutions to the equation 2x(x^2-3)=0 ?
The solutions to the equation 2x(x^2-3)=0 are x=0,x=-sqrt(3),x=sqrt(3)
Find the zeros of 2x(x^2-3)=0
The zeros of 2x(x^2-3)=0 are x=0,x=-sqrt(3),x=sqrt(3)