What are the solutions to the equation 3x^3+12x^2-9x=3x ?

The solutions to the equation 3x^3+12x^2-9x=3x are x=0,x=2(sqrt(2)-1),x=-2(1+sqrt(2))

Find the zeros of 3x^3+12x^2-9x=3x

The zeros of 3x^3+12x^2-9x=3x are x=0,x=2(sqrt(2)-1),x=-2(1+sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{3} + 12 x^{2} - 9 x = 3 x

x = 0, x = 2 (2 - 1), x = - 2 (1 + 2)

Decimal Notation

x = 0, x = 0.82842 \dots, x = - 4.82842 \dots

Solution steps

3 x^{3} + 12 x^{2} - 9 x = 3 x

Move

3 x

to the left side

3 x^{3} + 12 x^{2} - 12 x = 0

Factor

3 x^{3} + 12 x^{2} - 12 x : 3 x (x^{2} + 4 x - 4)

3 x (x^{2} + 4 x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 4 x - 4 = 0

Solve

x^{2} + 4 x - 4 = 0 : x = 2 (2 - 1), x = - 2 (1 + 2)

The solutions are

x = 0, x = 2 (2 - 1), x = - 2 (1 + 2)

x^{3} = e^{6}

(9 x^{2} + 1)^{2} = 0

2 z^{6} - 15 z^{3} - 27 = 0

(x^{2} + 7 x + 49) (x - 7) = 218

4 x^{3} - 2 x^{2} + 3 x - 1 = 0

What are the solutions to the equation 3x^3+12x^2-9x=3x ?
The solutions to the equation 3x^3+12x^2-9x=3x are x=0,x=2(sqrt(2)-1),x=-2(1+sqrt(2))
Find the zeros of 3x^3+12x^2-9x=3x
The zeros of 3x^3+12x^2-9x=3x are x=0,x=2(sqrt(2)-1),x=-2(1+sqrt(2))