What are the solutions to the equation 9x^2-29x-28=0 ?

The solutions to the equation 9x^2-29x-28=0 are x=4,x=-7/9

Find the zeros of 9x^2-29x-28=0

The zeros of 9x^2-29x-28=0 are x=4,x=-7/9

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9 x^{2} - 29 x - 28 = 0

x = 4, x = - \frac{7}{9}

Solution steps

9 x^{2} - 29 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 9 ( - 28 )}{2 \cdot 9}

(- 29)^{2} - 4 \cdot 9 (- 28) = 43

x_{1, 2} = \frac{- ( - 29 ) \pm 43}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 43}{2 \cdot 9}, x_{2} = \frac{- ( - 29 ) - 43}{2 \cdot 9}

x = \frac{- ( - 29 ) + 43}{2 \cdot 9} : 4

x = \frac{- ( - 29 ) - 43}{2 \cdot 9} : - \frac{7}{9}

The solutions to the quadratic equation are:

x = 4, x = - \frac{7}{9}

- 10 > z - 18

(\frac{10}{2})^{2}

t^{2} - 81

5 x^{2} - 20 x + 100

\frac{ln ( 8 )}{ln ( 2 )}

What are the solutions to the equation 9x^2-29x-28=0 ?
The solutions to the equation 9x^2-29x-28=0 are x=4,x=-7/9
Find the zeros of 9x^2-29x-28=0
The zeros of 9x^2-29x-28=0 are x=4,x=-7/9