What is the answer to solvefor x,g=f+f(sqrt(x)) ?

The answer to solvefor x,g=f+f(sqrt(x)) is x=(g^2}{f^2}-\frac{2g)/f+1

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solvefor x,g=f+f(sqrt(x))

solve for

x, g = f + f (x)

x = \frac{g ^{2}}{f ^{2}} - \frac{2 g}{f} + 1

Solution steps

g = f + f (x)

Switch sides

f + f x = g

Move

f

to the right side

f x = g - f

Divide both sides by

f

x = \frac{g - f}{f}

Square both sides:

x = \frac{g ^{2}}{f ^{2}} - \frac{2 g}{f} + 1

x = \frac{g ^{2}}{f ^{2}} - \frac{2 g}{f} + 1

x^{- \frac{4}{3}} = \frac{1}{256}

x - 2 = 3 x^{2} + x + 1

k, x = k^{- \frac{1}{3}}

- x^{2} + 2 x + 1 = x

5 x - 6 = 3 x + 4

What is the answer to solvefor x,g=f+f(sqrt(x)) ?
The answer to solvefor x,g=f+f(sqrt(x)) is x=(g^2}{f^2}-\frac{2g)/f+1