What are the solutions to the equation 8t^2+8t+2=0 ?

The solutions to the equation 8t^2+8t+2=0 are t=-1/2

Find the zeros of 8t^2+8t+2=0

The zeros of 8t^2+8t+2=0 are t=-1/2

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8 t^{2} + 8 t + 2 = 0

t = - \frac{1}{2}

Solution steps

8 t^{2} + 8 t + 2 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

8^{2} - 4 \cdot 8 \cdot 2 = 0

t_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 8}

t = \frac{- 8}{2 \cdot 8}

\frac{- 8}{2 \cdot 8} = - \frac{1}{2}

t = - \frac{1}{2}

The solution to the quadratic equation is:

t = - \frac{1}{2}

16 u^{2} - 40 u = - 25

1 - 2 x^{2} = 0

3 (7) + 9 (2) < - 18

g^{3} - 3 g^{2} - 2 g + 6

25 a^{2} - 40 a = - 16

What are the solutions to the equation 8t^2+8t+2=0 ?
The solutions to the equation 8t^2+8t+2=0 are t=-1/2
Find the zeros of 8t^2+8t+2=0
The zeros of 8t^2+8t+2=0 are t=-1/2