What is the answer to sqrt(x^2-3x+2)=0 ?

The answer to sqrt(x^2-3x+2)=0 is x=2,x=1

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sqrt(x^2-3x+2)=0

x^{2} - 3 x + 2 = 0

x = 2, x = 1

Solution steps

x^{2} - 3 x + 2 = 0

Square both sides:

x^{2} - 3 x + 2 = 0

x^{2} - 3 x + 2 = 0

Solve

x^{2} - 3 x + 2 = 0 : x = 2, x = 1

x = 2, x = 1

Verify Solutions:

x = 2

True

, x = 1

True

The solutions are

x = 2, x = 1

2 y + 6 + 3 = y + 2

x + 1 = x + 2

9 = n^{\frac{2}{3}}

x + 10 - x - 6 = 2

3 = 2 x^{2} - 5 x + 39 - x

What is the answer to sqrt(x^2-3x+2)=0 ?
The answer to sqrt(x^2-3x+2)=0 is x=2,x=1
Solve for x: sqrt(x^2-3x+2)=0
The solution is x=2,x=1