What is the answer to sqrt(16-2x)=2+sqrt(36+6x) ?

The answer to sqrt(16-2x)=2+sqrt(36+6x) is x=-9/2

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sqrt(16-2x)=2+sqrt(36+6x)

16 - 2 x = 2 + 36 + 6 x

x = - \frac{9}{2}

Decimal Notation

x = - 4.5

Solution steps

16 - 2 x = 2 + 36 + 6 x

Remove square roots

64 x^{2} + 384 x + 576 = 576 + 96 x

Solve

64 x^{2} + 384 x + 576 = 576 + 96 x : x = 0, x = - \frac{9}{2}

x = 0, x = - \frac{9}{2}

Verify Solutions:

x = 0

False

, x = - \frac{9}{2}

True

The solution is

x = - \frac{9}{2}

5 + 2 x + 5 = x

6 x + 16 + 3 x = 4 x

5 = (2 + 1)^{2} + (k - 1)^{2}

\frac{x ^{3} - 1}{x - 1} = 6.5

2 x + 11 = x + 6

What is the answer to sqrt(16-2x)=2+sqrt(36+6x) ?
The answer to sqrt(16-2x)=2+sqrt(36+6x) is x=-9/2
Solve for x: sqrt(16-2x)=2+sqrt(36+6x)
The solution is x=-9/2