What is the answer to solvefor x,x+1-2sqrt(x+4)=0 ?

The answer to solvefor x,x+1-2sqrt(x+4)=0 is x=5

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solvefor x,x+1-2sqrt(x+4)=0

x, x + 1 - 2 x + 4 = 0

x = 5

Solution steps

x + 1 - 2 x + 4 = 0

Remove square roots

4 x + 16 = x^{2} + 2 x + 1

Solve

4 x + 16 = x^{2} + 2 x + 1 : x = 5, x = - 3

x = 5, x = - 3

Verify Solutions:

x = 5

True

, x = - 3

False

The solution is

x = 5

2 x - 1 - 12 - 3 x = 0

x^{\frac{2}{9}} = 2

x + 2 + 2 = x

2 x^{2} = 1

x, y = 4 - 4 x

What is the answer to solvefor x,x+1-2sqrt(x+4)=0 ?
The answer to solvefor x,x+1-2sqrt(x+4)=0 is x=5