What is the answer to 0=4-sqrt(0+y^2) ?

The answer to 0=4-sqrt(0+y^2) is y=4,y=-4

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0=4-sqrt(0+y^2)

0 = 4 - 0 + y^{2}

y = 4, y = - 4

Solution steps

0 = 4 - 0 + y^{2}

Move

0 + y^{2}

to the left side

0 + y^{2} = 4

Square both sides:

y^{2} = 16

y^{2} = 16

Solve

y^{2} = 16 : y = 4, y = - 4

y = 4, y = - 4

Verify Solutions:

y = 4

True

, y = - 4

True

The solutions are

y = 4, y = - 4

x + 1 = 3 x + 2

(2 + 1)^{2} + (k - 1)^{2} = 5

x + 3 + x = x

x^{- \frac{1}{4}} = 2

What is the answer to 0=4-sqrt(0+y^2) ?
The answer to 0=4-sqrt(0+y^2) is y=4,y=-4
Solve for y: 0=4-sqrt(0+y^2)
The solution is y=4,y=-4