What is the answer to 3=sqrt(2x^2-17x) ?

The answer to 3=sqrt(2x^2-17x) is x=9,x=-1/2

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3=sqrt(2x^2-17x)

3 = 2 x^{2} - 17 x

x = 9, x = - \frac{1}{2}

Decimal Notation

x = 9, x = - 0.5

Solution steps

3 = 2 x^{2} - 17 x

Square both sides:

9 = 2 x^{2} - 17 x

9 = 2 x^{2} - 17 x

Solve

9 = 2 x^{2} - 17 x : x = 9, x = - \frac{1}{2}

x = 9, x = - \frac{1}{2}

Verify Solutions:

x = 9

True

, x = - \frac{1}{2}

True

The solutions are

x = 9, x = - \frac{1}{2}

5 x^{2} + 3 x - 11 = 4 x - 7

16 - x^{2} + x^{2} = 0

(x - 3)^{2} + (- 1 - 2)^{2} = 4

7 x + 4 = 5

\frac{x - 1}{x + 1} = 1

What is the answer to 3=sqrt(2x^2-17x) ?
The answer to 3=sqrt(2x^2-17x) is x=9,x=-1/2
Solve for x: 3=sqrt(2x^2-17x)
The solution is x=9,x=-1/2