What is the answer to 4=sqrt((3-x)^2+(2-1)^2) ?

The answer to 4=sqrt((3-x)^2+(2-1)^2) is x=3+sqrt(15),x=3-sqrt(15)

Solve for x: 4=sqrt((3-x)^2+(2-1)^2)

The solution is x=3+sqrt(15),x=3-sqrt(15)

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4 = (3 - x)^{2} + (2 - 1)^{2}

x = 3 + 15, x = 3 - 15

Decimal Notation

x = 6.87298 \dots, x = - 0.87298 \dots

Solution steps

4 = (3 - x)^{2} + (2 - 1)^{2}

Square both sides:

16 = x^{2} - 6 x + 10

16 = x^{2} - 6 x + 10

Solve

16 = x^{2} - 6 x + 10 : x = 3 + 15, x = 3 - 15

x = 3 + 15, x = 3 - 15

Verify Solutions:

x = 3 + 15

True

, x = 3 - 15

True

The solutions are

x = 3 + 15, x = 3 - 15

x^{2} - 2 x + 1 = x - 1

3 - y - 6 = 0

1 + x^{2} = 5 - x^{2}

x = 12 - x

What is the answer to 4=sqrt((3-x)^2+(2-1)^2) ?
The answer to 4=sqrt((3-x)^2+(2-1)^2) is x=3+sqrt(15),x=3-sqrt(15)
Solve for x: 4=sqrt((3-x)^2+(2-1)^2)
The solution is x=3+sqrt(15),x=3-sqrt(15)