What is the answer to sqrt(x^2+x+1)=x-1 ?

The answer to sqrt(x^2+x+1)=x-1 is No Solution for x\in\mathbb{R}

Solve for x: sqrt(x^2+x+1)=x-1

The solution is No Solution for x\in\mathbb{R}

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x^{2} + x + 1 = x - 1

No Solution for x \in R

Solution steps

x^{2} + x + 1 = x - 1

Square both sides:

x^{2} + x + 1 = x^{2} - 2 x + 1

x^{2} + x + 1 = x^{2} - 2 x + 1

Solve

x^{2} + x + 1 = x^{2} - 2 x + 1 : x = 0

x = 0

Verify Solutions:

x = 0

False

The solution is

No Solution for x \in R

y, x = - 1 - y

d, q = F d + 4

x + 2 x - 3 = 0

x^{\frac{4}{3}} = 9

y, x = 2 3 - y

What is the answer to sqrt(x^2+x+1)=x-1 ?
The answer to sqrt(x^2+x+1)=x-1 is No Solution for x\in\mathbb{R}
Solve for x: sqrt(x^2+x+1)=x-1
The solution is No Solution for x\in\mathbb{R}