What is the answer to x+1=sqrt(3x^2+3x-20) ?

The answer to x+1=sqrt(3x^2+3x-20) is x=3

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x+1=sqrt(3x^2+3x-20)

x + 1 = 3 x^{2} + 3 x - 20

x = 3

Solution steps

x + 1 = 3 x^{2} + 3 x - 20

Square both sides:

x^{2} + 2 x + 1 = 3 x^{2} + 3 x - 20

x^{2} + 2 x + 1 = 3 x^{2} + 3 x - 20

Solve

x^{2} + 2 x + 1 = 3 x^{2} + 3 x - 20 : x = - \frac{7}{2}, x = 3

x = - \frac{7}{2}, x = 3

Verify Solutions:

x = - \frac{7}{2}

False

, x = 3

True

The solution is

x = 3

18 - x = x + 2

- 4 + 5 x = x

t, x = 4 + 8 t + 4

4 = x + 2 x - 7

1 - x^{2} = a x

What is the answer to x+1=sqrt(3x^2+3x-20) ?
The answer to x+1=sqrt(3x^2+3x-20) is x=3
Solve for x: x+1=sqrt(3x^2+3x-20)
The solution is x=3