What is the answer to solvefor x,g^{-1}(x)=x^{0.5} ?

The answer to solvefor x,g^{-1}(x)=x^{0.5} is x=g^2 {g>0},x=0 {g 0}

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solvefor x,g^{-1}(x)=x^{0.5}

solve for

x, g^{- 1} (x) = x^{0.5}

x = g^{2} {g > 0}, x = 0 {g < 0 or g > 0}

Solution steps

g^{- 1} (x) = x^{0.5}

Expand

g^{- 1} x : \frac{x}{g}

\frac{x}{g} = x^{0.5}

Square both sides:

\frac{x ^{2}}{g ^{2}} = x

\frac{x ^{2}}{g ^{2}} = x

Solve

\frac{x ^{2}}{g ^{2}} = x : x = g^{2}, x = 0

x = g^{2}, x = 0

Verify Solutions:

x = g^{2} {g > 0}, x = 0 {g < 0 or g > 0}

The solutions are

x = g^{2} {g > 0}, x = 0 {g < 0 or g > 0}

14 = 1 - 4 x + 9

x, x^{2} + x + y = 10

5 x - 39 - 7 = - 6

y, 2 x^{2} = - 2 y

19 - 2 x = x + 8

What is the answer to solvefor x,g^{-1}(x)=x^{0.5} ?
The answer to solvefor x,g^{-1}(x)=x^{0.5} is x=g^2 {g>0},x=0 {g<0\lor g>0}