What is the answer to x^2+x-8=sqrt(x^2+x+4) ?

The answer to x^2+x-8=sqrt(x^2+x+4) is x=3,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+x-8=sqrt(x^2+x+4)

x^{2} + x - 8 = x^{2} + x + 4

x = 3, x = - 4

Solution steps

x^{2} + x - 8 = x^{2} + x + 4

Square both sides:

x^{4} + 2 x^{3} - 15 x^{2} - 16 x + 64 = x^{2} + x + 4

x^{4} + 2 x^{3} - 15 x^{2} - 16 x + 64 = x^{2} + x + 4

Solve

x^{4} + 2 x^{3} - 15 x^{2} - 16 x + 64 = x^{2} + x + 4 : x = 3, x = - 4, x = \frac{- 1 + 21}{2}, x = \frac{- 1 - 21}{2}

x = 3, x = - 4, x = \frac{- 1 + 21}{2}, x = \frac{- 1 - 21}{2}

Verify Solutions:

x = 3

True

, x = - 4

True

, x = \frac{- 1 + 21}{2}

False

, x = \frac{- 1 - 21}{2}

False

The solutions are

x = 3, x = - 4

4 x = 40 - 4 (68 - x^{2})

1 + (x - 2)^{\frac{2}{3}} = 0

10 x + 100 + 10 = x

What is the answer to x^2+x-8=sqrt(x^2+x+4) ?
The answer to x^2+x-8=sqrt(x^2+x+4) is x=3,x=-4
Solve for x: x^2+x-8=sqrt(x^2+x+4)
The solution is x=3,x=-4