What are the solutions to the equation x^2+11x=0 ?

The solutions to the equation x^2+11x=0 are x=0,x=-11

Find the zeros of x^2+11x=0

The zeros of x^2+11x=0 are x=0,x=-11

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x^{2} + 11 x = 0

x = 0, x = - 11

Solution steps

x^{2} + 11 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 0 = 11

x_{1, 2} = \frac{- 11 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 11}{2 \cdot 1}, x_{2} = \frac{- 11 - 11}{2 \cdot 1}

x = \frac{- 11 + 11}{2 \cdot 1} : 0

x = \frac{- 11 - 11}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = 0, x = - 11

5 x^{2} + 6 x - 32 = 0

(2 x + 1) (x - 2) (3 x - 4) \leq 0

16 x^{4} - (y - 2 z)^{2}

2 x^{2} - 4 x y + 2 y^{2}

\frac{i - 2}{i - 1}

What are the solutions to the equation x^2+11x=0 ?
The solutions to the equation x^2+11x=0 are x=0,x=-11
Find the zeros of x^2+11x=0
The zeros of x^2+11x=0 are x=0,x=-11