What are the solutions to the equation a^2+6a+8=0 ?

The solutions to the equation a^2+6a+8=0 are a=-2,a=-4

Find the zeros of a^2+6a+8=0

The zeros of a^2+6a+8=0 are a=-2,a=-4

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a^{2} + 6 a + 8 = 0

a = - 2, a = - 4

Solution steps

a^{2} + 6 a + 8 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

a_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 6 + 2}{2 \cdot 1}, a_{2} = \frac{- 6 - 2}{2 \cdot 1}

a = \frac{- 6 + 2}{2 \cdot 1} : - 2

a = \frac{- 6 - 2}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

a = - 2, a = - 4

\frac{1}{\frac{1}{2} + \frac{1}{2}}

k^{2} + 9 k + 20 = 0

5 x^{2} + 4 x - 2 = 0

- 5 ∣ 5 x - 6 ∣ - 4 = - 49

\frac{4 ^{3}}{4 ^{3}}

What are the solutions to the equation a^2+6a+8=0 ?
The solutions to the equation a^2+6a+8=0 are a=-2,a=-4
Find the zeros of a^2+6a+8=0
The zeros of a^2+6a+8=0 are a=-2,a=-4