What is the answer to log_{4}(2-x)=log_{16}(13-4x) ?

The answer to log_{4}(2-x)=log_{16}(13-4x) is x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{4}(2-x)=log_{16}(13-4x)

lo g_{4} (2 - x) = lo g_{16} (13 - 4 x)

x = - 3

Solution steps

lo g_{4} (2 - x) = lo g_{16} (13 - 4 x)

Apply log rules

(2 - x)^{2} = 13 - 4 x

Solve

(2 - x)^{2} = 13 - 4 x : x = 3, x = - 3

x = 3, x = - 3

Verify Solutions:

x = 3

False

, x = - 3

True

The solution is

x = - 3

ln (x) = 10

lo g_{4} (x) = lo g_{4} (8 - x)

ln (3 x) + ln (x + 2) = 0

ln (x) + ln (x - 2) = ln (3)

lo g_{6} (x) = - 2

What is the answer to log_{4}(2-x)=log_{16}(13-4x) ?
The answer to log_{4}(2-x)=log_{16}(13-4x) is x=-3
Solve for x: log_{4}(2-x)=log_{16}(13-4x)
The solution is x=-3