What is the answer to log_{10}(x)+log_{10}(x+21)=2 ?

The answer to log_{10}(x)+log_{10}(x+21)=2 is x=4

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log_{10}(x)+log_{10}(x+21)=2

lo g_{10} (x) + lo g_{10} (x + 21) = 2

x = 4

Solution steps

lo g_{10} (x) + lo g_{10} (x + 21) = 2

Apply log rules

x (x + 21) = 100

Solve

x (x + 21) = 100 : x = 4, x = - 25

x = 4, x = - 25

Verify Solutions:

x = 4

True

, x = - 25

False

The solution is

x = 4

lo g_{2} (x) + lo g_{2} (x - 7) = 3

lo g_{2} (x) + lo g_{4} (x) = 2

lo g_{2} (x + 3) + lo g_{2} (x - 3) = 4

lo g_{x} (81) = 2

lo g_{m} (32) = 5

What is the answer to log_{10}(x)+log_{10}(x+21)=2 ?
The answer to log_{10}(x)+log_{10}(x+21)=2 is x=4
Solve for x: log_{10}(x)+log_{10}(x+21)=2
The solution is x=4